You are not logged in.
Pages: 1
Two circles intersect at A and B. The tangents at C and D intersect at T which is an extension of AB. If CBD is a straight line, prove that,
a) angle TAC = angle TAD
b) TC = TD
Thanks... I've been at this one for a long time
Offline
Hint: start by proving this theorem:
A circle and a point A is given. Let a line through A intersect the circle in points B and C, and draw a line PD, such that PD is a tangent to the circle with tangent point D. Then |AB|*|AC|=|AD|².
Your problem will follow quite easily from this theorem.
Offline
Wow! That theorem helped a lot Kurre
In the meantime I had solved the problem by proving that ACDT is cyclic, but using that theorem it all comes together in a few simple steps!
Offline
Pages: 1