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bananaphone
messege deleted
Last edited by bananaphone (2008-05-01 08:05:20)
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Here's a few tips:
First, set each f(x)=0. This is where the graph crosses the x-axis.
Now either factor, complete the square, or use the quadratic formula:
Last edited by simron (2008-04-30 08:41:53)
Linux FTW
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I got -1,-10 is that right?
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simron, these were meant to be factored without the quadratic method.
bananaphone, you need to make the equations into the following form:
(x - a)(x - b)
So if we were to multiply this out, we get:
x^2 - (a+b)x + ab
So if you look at the first one, we see that ab = -11, and so one possibility for a and b is 1 and -11. Now we need a + b to be -10. But 1 + -11 = -10, as we needed. SO
x^2 - (1 + -11)x + 1*-11 = x^2 + 10x - 11
And we get:
x^2 + 10x - 11 = (x - 1)(x+11)
This tells us the roots are 1 and -11.
There is no square key on my laptop
Your keys are round?
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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no my keys are square wtf?
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...just a joke...
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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