Math Is Fun Forum
Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °
You are not logged in.
- Topics: Active | Unanswered
Pages: 1
#1 2008-04-16 03:35:22
- hotgal24
- Member
- Registered: 2008-01-12
- Posts: 4
Solve this And You are a Genius
Offline
#2 2008-04-16 05:07:22
- TheDude
- Member
- Registered: 2007-10-23
- Posts: 361
Re: Solve this And You are a Genius
Edit: Whoops, that's not right.
Last edited by TheDude (2008-04-16 05:09:04)
Wrap it in bacon
Offline
#3 2008-04-16 11:34:28
- Avon
- Member
- Registered: 2007-06-28
- Posts: 80
Re: Solve this And You are a Genius
Any sequence of the form
satisfies the recurrence relation
In Professor Umbuguio's forumula we have
It is easy to check that are all divisible by 1946.
Since
are all integers, we can use the recurrence relation to prove by induction that is divisible by 1946 for allOffline
Pages: 1