Math Is Fun Forum

adam thomson

Guest

integration

2
∫(4x+3x+7) = i got 45.16 - 9.83
1

1.5
∫ (3t to minus 4 + 2t minus 2) i got 0.276 - - 24.538
0.5

1
∫3 (x+5)4 dx = i got 3/5 (x+5)5
0

s = 0.2 (4+7t-2t -t ) velocity at 2 secs , time when velocity is zero , acceleration when t = 1.5 , distance traveld after 4 secs?

a, 7-4t-1 = -2m/s x 0.2

b , 7-4t -1 i used the rule -b +/- √b2 - 4 x A x C = 0.705 multiplied by 0.2 and -0.187 multiplied by 0.2.

c , 7-4t-1 = 4m/s x 0.2

d , i didnt know how to do question d

John E. Franklin

Member

Registered: 2005-08-29

Posts: 3,588

Re: integration

2
∫(4x+3x+7)
1

(4/3)x^3 + (3/2)x^2 + 7x , where x = 2 subtract when x = 1.

Should be about 20 5/6 because
2^3 - 1^3 is 8 - 1 is 7 and (4/3)(7) first term is 9 1/3.
Now the 2nd term is (3/2)(2^2 - 1^2) is 4.5.
And 3rd term is (2-1)(7) is 7.
Add'm up.  20 5/6

---

igloo myrtilles fourmis

adam thomson

Guest

Re: integration

does that mean the rest are ok or ???

Daniel123

Member

Registered: 2007-05-23

Posts: 663

Re: integration

What do you mean by ''?