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#1 2008-03-04 22:12:11

Identity
Member
Registered: 2007-04-18
Posts: 934

Condition of divisibility

If

divides
then what condition must there be?

Using the factor theorem I get

, which is what the answer says.

But doesn't there have to be ANOTHER restriction for this to be true?

i.e.

So then doesn't

OR is this second restriction Not necessary???

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#2 2008-03-05 00:38:17

JaneFairfax
Member
Registered: 2007-02-23
Posts: 6,868

Re: Condition of divisibility

What is c? If c can be complex as well as real, then there is no need for any condition on a and b. The condition

is only for required for c to be real.

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#3 2008-03-05 02:28:33

Identity
Member
Registered: 2007-04-18
Posts: 934

Re: Condition of divisibility

We haven't learnt complex numbers yet so I assume c is real.

Thanks Jane

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#4 2008-03-07 11:39:22

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: Condition of divisibility

Given that a quadratic has a single real root, it must be that there are two real roots, counting a repeated root as two roots.  That is the equivalent of your statement.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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