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How would you solve e^x = x² - 1?
EDIT: This is the 7777th topic
Last edited by Daniel123 (2008-02-16 11:54:14)
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Plotting the graphs shows that there is a solution in x between −2 and −1. Otherwise I dont think there is any way of expressing the solution in closed form.
EDIT: This is the 7777th topic
At the moment, the topic 0.9999....(recurring) = 1? has 911 replies.
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Ahh good. I was getting myself confused.. I'm not having a good maths day.
EDIT: THANKS. I really am tired.. forgetting my manners.
Last edited by Daniel123 (2008-02-16 12:14:53)
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At the moment, the topic 0.9999....(recurring) = 1? has 911 replies.
And the two topics below have 9 then 11 replies.
Last edited by Daniel123 (2008-02-16 12:20:17)
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You can get it to as many decimal places as are on your calculator by putting -1.5 = (or some number close to that), and then putting -√(eAns+1) and pressing = lots of times.
As for an exact analytic answer, I don't see a way of getting one either.
Why did the vector cross the road?
It wanted to be normal.
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The graph: Plot of e^x vs x^2-1 they cross over around -1.1477576
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
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