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#126 2007-12-16 21:38:55
- ganesh
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Re: *** Problems
Absolutely right, JohnnyReinB! Very well done!!!
Character is who you are when no one is looking.
#127 2007-12-19 00:34:25
- ganesh
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Re: *** Problems
47. I have four marked weights. The sum of the four weights is 40 kilograms. With a pair of scales and these four weights, I can distribute any quantity from 1 kilogram to 40 kilograms (whole numbers). What are the four weights?
48. A pole stands at the mid-point of side AB of a triangular plot ABC. Find the height of the pole if the angles of elevation of the top of the pole at A, B, and C are 45°, 45°, and 30° respectively and BC=AC=150 meters.
Character is who you are when no one is looking.
#128 2007-12-25 20:52:55
- ganesh
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Re: *** Problems
ganesh wrote:
#41. Create a 4X4 Magic Square using the numbers 1-16 without referring. If you can do it in less than five minutes, thats a very good performance.
Here's the solution to the problem!
Character is who you are when no one is looking.
#129 2008-01-06 00:20:22
- JohnnyReinB
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Re: *** Problems
"There is not a difference between an in-law and an outlaw, except maybe that an outlaw is wanted"
Nisi Quam Primum, Nequequam
#130 2008-01-06 01:25:54
- ganesh
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Re: *** Problems
Thank you for answering to activate the topic.
However, your answer isn't correct, JohnnyReinB!!!
Character is who you are when no one is looking.
#131 2008-01-06 14:55:25
- JohnnyReinB
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Re: *** Problems
But tell me, does scales create a possibility of the weights canceling out?
"There is not a difference between an in-law and an outlaw, except maybe that an outlaw is wanted"
Nisi Quam Primum, Nequequam
#132 2008-01-06 17:39:44
- ganesh
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Re: *** Problems
You may use both the pans. You may also put some wights on the left and some on the right to get the required weight.
Character is who you are when no one is looking.
#133 2008-01-07 01:35:11
- ganesh
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Re: *** Problems
49. The Greatest Common Divisor of
Character is who you are when no one is looking.
#134 2008-01-08 18:59:24
- ganesh
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Re: *** Problems
50. What is the value of
Character is who you are when no one is looking.
#135 2008-01-13 17:27:19
- JohnnyReinB
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Re: *** Problems
"There is not a difference between an in-law and an outlaw, except maybe that an outlaw is wanted"
Nisi Quam Primum, Nequequam
#136 2008-01-13 18:00:39
- ganesh
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Re: *** Problems
No, not (x+y), JohnnyReinB!
Character is who you are when no one is looking.
#137 2008-01-13 18:09:51
- JohnnyReinB
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Re: *** Problems
x-y?
"There is not a difference between an in-law and an outlaw, except maybe that an outlaw is wanted"
Nisi Quam Primum, Nequequam
#138 2008-01-13 18:20:11
- ganesh
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Re: *** Problems
Yes, you are correct!!!
Well done, JohnnyReinB!!!
Character is who you are when no one is looking.
#139 2008-01-13 18:27:29
- JohnnyReinB
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Re: *** Problems
Hehe, there were only two choices, anyway, Ganesh.
"There is not a difference between an in-law and an outlaw, except maybe that an outlaw is wanted"
Nisi Quam Primum, Nequequam
#140 2008-01-19 08:13:31
- lester_day
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Re: *** Problems
ganesh wrote:
***1
Two numbers x and y are chosen at random from the set [1,2,3,4,..........,3n]. What is the probability that x² -y² is divisible by 3?
#141 2008-01-19 08:16:32
#142 2008-01-19 08:18:33
#143 2008-01-19 08:19:07
#144 2008-01-19 08:27:31
- lester_day
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Re: *** Problems
ganesh wrote:
***2
Solve for x.
(x-1)³+(x-2)³+(x-3)³+(x-4)³+(x-5)³=0
#145 2008-01-19 08:29:58
- lester_day
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Re: *** Problems
I make it 3. The middle term is zero and the other terms cancels out.
#146 2008-01-20 17:19:09
- ganesh
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Re: *** Problems
Very well done, lester_day! Your answers are correct!!!
Outstanding!!!
Character is who you are when no one is looking.
#147 2008-08-14 02:25:58
- Sudeep
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Re: *** Problems
Let the quadratic ax^2 + bx + c be such that a, b, c are distinct and each of a, b, c belong to {1, 2, 3, ..., n} such that x+1 divides ax^2 + bx + c.
If the number of such quadratic polynomials are < 99, then max (n) is ??
#148 2008-08-14 03:34:59
- mathsyperson
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Re: *** Problems
max(n) = 15
Why did the vector cross the road?
It wanted to be normal.
#149 2008-08-14 03:58:10
#150 2008-11-18 01:07:03
- ganesh
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Re: *** Problems
#51. Complete the next two numbers in the series of Perfect Numbers:-
6, 28, ____, _______.
Character is who you are when no one is looking.