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**tony123****Member**- Registered: 2007-08-03
- Posts: 189

How many six digits perfict square are there each having the property that if each digit is increased by one the resulting number is also a perfect square

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 82,672

Hi tony123;

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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**phrontister****Real Member**- From: The Land of Tomorrow
- Registered: 2009-07-12
- Posts: 3,819

Hi Bobby,

"The good news about computers is that they do what you tell them to do. The bad news is that they do what you tell them to do." - Ted Nelson

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 82,672

Hi;

Good to see you! You are right 125 is an extra solution that does not fit. The method I used came up with all the solutions not just the six digit ones.

I have added that fact to the original post. Appears I just made a silly mistake of being unable to count to 6 correctly.

**In mathematics, you don't understand things. You just get used to them.I have the result, but I do not yet know how to get it.All physicists, and a good many quite respectable mathematicians are contemptuous about proof.**

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