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Hello.
A smooth bead B is threaded on a light inextensible string. The ends of the string are attached to two fixed points A and C on the same horizontal level. The bead is held in equilibrium by a horizontal force of magnitude 6N acting parallel to AC. The bead B is vertically below C and angle BAC as θ. Given that tanθ = 3/4, find:
a) the tension in the string
The question implies that the strings have equal tension, but I am not sure why this is? I dont have any problem doing the actual question, it's just this bit I'm a bit confused about.
Thanks.
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the string is inextensible, therefore the tension throughout the string is equal in magnitude. For the string to have a differing tension in the vertical and diagonal part, the two parts would have to be stretched by different factors, since its inextensible thats not the case.
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Ahh right ok, thanks. I have M1 on friday. Do you have many modules?
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ive got M2 wednesday, then FP1 and D1 over the next two weeks - my AS in Fmaths.
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There must be a downward component on the bead too, or the bead would move up and to the right.
I'm assuming the hole in the bead is curved and frictionless.
igloo myrtilles fourmis
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its weight john.
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