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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

Answer to #7 :- Take a look at the graphs on the cartesian plane. Now, do you know why they're grouped in that way?

Character is who you are when no one is looking.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

#19. A person walking 5/6 of his usual rate is 40 minutes late. What is his usual time?

Character is who you are when no one is looking.

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**JohnnyReinB****Member**- Registered: 2007-10-08
- Posts: 453

*"There is not a difference between an in-law and an outlaw, except maybe that an outlaw is wanted" *

Nisi Quam Primum, Nequequam

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

Absolutely right, JohnnyReinB!!!**Congratulations!!!**

Character is who you are when no one is looking.

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**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

Answer to #18:-

Thats right, Janefairfax!

Character is who you are when no one is looking.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

#20. A shopkeeper marks his goods at such a price that after allowing a discount of 12½% on the marked price, he still earns a profit of 10%. Find the marked price of an article which costs him $4900.

#21. Sam borrowed a sum of money and returned it in three equal instalments of $35,152 each. If the rate of interest charged was 16% per annum compounded quarterly, find the sum borrowed by him.

Character is who you are when no one is looking.

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**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

Answer to #20:-

Perfectly right, Janefairfax!

#22. Find the area of a trapezium whose parallel sides are 77 cm and 60 cm; and the other sides are 25 cm and 26 cm.

Character is who you are when no one is looking.

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**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

Answer to #22:-

Perfectly right, Janefairfax!

Character is who you are when no one is looking.

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**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

Answer to #17:-

Please check your answer as I am getting a different one!

Character is who you are when no one is looking.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

#22. What is the number of solutions of the following equation?

#23. What are the values of x if

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

#24. If

are in arithmetic progression, then what is the value of x?Character is who you are when no one is looking.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

#25. What is the value of x if

Character is who you are when no one is looking.

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**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

Argh!

Hopefully this one is correct.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

JaneFairfax,

Character is who you are when no one is looking.

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**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

I know. I divided by 2 twice.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

Yet another chance for you, Jane!

Character is who you are when no one is looking.

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**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

I beg to differ this time, Ganesh. I do believe my last answer for #17 is the correct one.

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**Identity****Member**- Registered: 2007-04-18
- Posts: 934

Amazing ganesh, I don't think i have ever seen you use the same picture twice

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**JaneFairfax****Member**- Registered: 2007-02-23
- Posts: 6,868

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

Answer to #17:-

The parallel sides are 60 cm and 46 cm.

The non-parallel sides are 13 cm and 15 cm.

Let the Trapezium be named ABCD where AB=46 cm, BC=15 cm, CD=60 cm, and DA=13 cm.

AB || CD.

Draw AE parallel to BC where E is a point on CD. Therefore, ABCE is a parallelogram, where AB=CE=46cm, BC=AE=15 cm. Area of the parallelogram = 46 x 15 = 690 sq.cm.

In triangle ADE, AD=13 cm, AE=15 cm, and DE=60cm - 46 cm = 14 cm.

Area of triangle ADE, where S=(13+14+15)/2=21 cm is

Therefore, total area of Trapezium ABCD is 690 sq.cm + 84 sq.cm = 774 sq.cm.

**To JaneFairfax : Please correct me if I am wrong. I tend to make a lot of mistakes in a hurry. Its too difficult to detect these mistakes when I check the second time.**

Character is who you are when no one is looking.

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**ganesh****Moderator**- Registered: 2005-06-28
- Posts: 15,152

Answer to #22:-

Correct, Identity!

Identity, I try not to use the same image twice. But then, there are two factors I wish to tell you. My fading memory as a result of my age fails sometimes. Second, there's a limited stock to choose from, and I keep rotating! Thanks for your observation, I shall try my best to make amends

Character is who you are when no one is looking.

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