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You are not logged in. #1 20071207 07:01:48
Geometric Progression ProblemFour numbers form a geometric progression. The sum of the four numbers is 13, the sum of their squares is 1261. Find the four numbers. #2 20071207 16:11:32
Re: Geometric Progression ProblemLet the numbers be 1/a, 1, a, and a². Character is who you are when no one is looking. #3 20071207 20:27:21
Re: Geometric Progression ProblemThose numbers should all be multiplied by an unknown constant to be completely general. Why did the vector cross the road? It wanted to be normal. #4 20071207 21:02:34
Re: Geometric Progression ProblemEdit: Oops. forgot about the Geometric Progression Last edited by NullRoot (20071207 23:30:32) Trillian: Five to one against and falling. Four to one against and falling… Three to one, two, one. Probability factor of one to one. We have normality. I repeat, we have normality. Anything you still can’t cope with is therefore your own problem. 