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#1 2007-11-20 03:41:38

James000
Guest

computing integral

i'm not sure how to approach this.  any help would be greatly appreciated!

integral of e^[-(x-1/2z)^2] dx

#2 2007-11-20 03:57:30

mikau
Member
Registered: 2005-08-22
Posts: 1,504

Re: computing integral

is that z supposed to be an x?


A logarithm is just a misspelled algorithm.

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#3 2007-11-20 04:09:47

James000
Guest

Re: computing integral

No, it's supposed to be a z (a constant).

#4 2007-11-22 08:00:37

freddogtgj
Member
Registered: 2006-12-02
Posts: 54

Re: computing integral

Can you not just expand the bracket so you are left with

and then use the rule for integrating e?

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#5 2007-11-22 09:25:46

Krizalid
Member
Registered: 2007-03-09
Posts: 51

Re: computing integral

James000 wrote:

i'm not sure how to approach this.  any help would be greatly appreciated!

integral of e^[-(x-1/2z)^2] dx

Sure. This makes sense if

That means that we're talking about the famous gaussian integral:

This can be proven in many ways. Polar transform is the common one.

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