Math Is Fun Forum

mrt

Guest

Logic Question

Hi. I've tried to do this question but i couldn't since there are two conditional logic propositions:

JaneFairfax

Member

Registered: 2007-02-23

Posts: 6,868

Re: Logic Question

Last edited by JaneFairfax (2007-09-26 10:32:38)

Ricky

Moderator

Registered: 2005-12-04

Posts: 3,791

Re: Logic Question

~(~p -> q) = ~(~p v ~q) = p & q

No?

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"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

JaneFairfax

Member

Registered: 2007-02-23

Posts: 6,868

Re: Logic Question

John E. Franklin

Member

Registered: 2005-08-29

Posts: 3,588

Re: Logic Question

In post #2 by Jane, it is in fact perfectly correct!!
And the "tautology" she is referring to means that
for any of the four combinations of p and q, the
result will always be a TRUE value.
So in electronics, we would say, the entire equation
boils down to LOGIC ONE, or True.

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igloo myrtilles fourmis

mrt

Guest

Re: Logic Question

oh cool thanks so much