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Hello everyone, I have the following:
S={(4,5),(4,6),(5,4),(6,6)}
What is SoS^-1?
Now I wrote that S^-1={(5,4),(6,4),(4,5),(6,6)}
So I should have:
{(4,4), (4,4), (5,5), (6,6)}
but the back of my book says that I should (5,6) and (6,5) as part of the solution. Can anyone explain?
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5 goes to 4 in S^-1, and 4 goes to both 5 and 6 in S. So 5 goes to 5 and 5 goes to 6. The same thing happens with 6.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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5 goes to 4 in S^-1, and 4 goes to both 5 and 6 in S. So 5 goes to 5 and 5 goes to 6. The same thing happens with 6.
How does that happen. I thought that you take the first elements of S and pair them with the second elements in S^-1. Since there are 4 pairs, you should get 4 pairs at the end right?
Last edited by MarkusD (2007-09-19 16:29:02)
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