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Last edited by tony123 (2007-08-04 03:33:21)
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I'll wager there's no analytic method to solve this... by inspection I have x=2 as one possible solution.
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Graphing it shows that -2 is also a value.
There are 10 types of people in the world, those who understand binary, those who don't, and those who can use induction.
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To prove that these are the only solutions, simple prove that the function is continuous, if x and y are positive with x < y, then f(x) < f(y), and if x and y are negative with x < y, then f(y) < f(x). This guarantees the existence of at most 2 solutions.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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Graphing it shows that -2 is also a value.
Or you could just note that
This would be simpler that plotting graphs.
Last edited by JaneFairfax (2007-12-18 13:02:08)
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