With some help I have now expanded our Sam Loyd Puzzles to more than 30.
Most of them with beautiful old illustrations.
See if you can solve them all!
Give me feedback here, too.
Awesome collection, I hope you keep adding to it. They are fun to play with.
On the "Question Of Time" problem, there are also other answers close to the following times:
igloo myrtilles fourmis
Love the Sam Loyd Puzzles, but have a discrepancy on the keys puzzle.
The key sentence for me was "since 6910 multiplied by 7 does not equal 83452". This implies that if it did equal 83452, that the arrangement of keys would be correct. Solving it along this line, I took the factors of 83452, and found that 20863 multiplied by 4 does equal 83452, so that is my answer. Did I miss something???
20863 multiplied by 4 does equal 83452
It does, but I think you are mis-interpreting what the puzzle is asking.
The picture shows ten keys with the digits 0 1 2 3 4 5 6 7 8 and 9 on them.
So you need to find an answer of the form <number A> times <number B> = <number C> where exactly the ten digits are used.
And the circular order of the digits must be maintained. So you could have eg. <5269107834> as the ring is endless.
The solution given does that. Yours has repeated digits and no 1, 7, or 9.
What I'm wondering is "Is this answer the only possibility?"
Over to you. (You did say you love puzzles)
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Thanks for the input, Bob! I didn't even notice that fact! I am going back to the puzzle to see what that looked like, re-reading the puzzle, and then considering your question. Thanks for the challenge Bob, I'll get back to you on that!
Di aka logical1