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Hey All,
how do determine the position and nature (i.e minimum, maximum or saddle point) of the stationary points of the function.
f(x,y)=x^2 - 4xy + y^3 + 4y
this is what I have done so far
dz/dx= 2x-4y
dz/dy=-4x+3y^2+4
d^2z/dxdy=-4
cheers
and thats where i get stuck, i havn't covered this yet in my studies
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looked up eigenvalues, and this is how i work it out (but you don't have to trust me here, im new to this )
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thanks lol
don't worry about it. we are all learning here.
how do you get ur x coordinates as 4/3 and 4
thanks
stationary points are where both partial derivitaves are 0
produces simultaenous equation in x and y, note that ive rearranged partial in x, to give x = 2y, which ive substituted into partial in y to find values of y, and then plug back into the partial for x, to find value of x given the value of y
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thanks
yes i can see what you have done.
but for
(4/3, 2/3), (4, 2)
where does the 4/3 and the 4 come from in the line above
do u substitute dem into a equation?
i substitute the two values of yinto x = 2y, derived from the partial derivitave in x
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oh I see!
thanks for that. I appreciate your help
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