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#1 2007-05-01 08:40:44

mat
Guest

parametric

can you please see if I have done the following correctly. cheers

calculate dy/dx = dy/dt / dx/dt in terms of parameter t

#2 2007-05-01 08:50:26

luca-deltodesco
Member
Registered: 2006-05-05
Posts: 1,470

Re: parametric

you arrive at the correct answer, but take care in your working out, you seem to be using dy/dx where you should be writing dy/dt etc

Last edited by luca-deltodesco (2007-05-01 08:51:18)


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#3 2007-05-01 18:05:00

mat
Guest

Re: parametric

Thank you.. and thanks for pointing out my mistake. cheers

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