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#1 2007-04-11 01:33:37

math123
Member
Registered: 2007-04-11
Posts: 1

Algebra

x and y are positive integers with the following two properties –
a) x3 – y3 is a perfect square, and
b) x2 – y2 is a perfect cube.
Find the smallest possible values of x and y.

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#2 2007-04-11 02:25:16

Stanley_Marsh
Member
Registered: 2006-12-13
Posts: 345

Re: Algebra

My first guess , is , x=10 , y=6 .

Last edited by Stanley_Marsh (2007-04-11 02:28:13)


Numbers are the essence of the Universe

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#3 2007-04-11 03:22:41

JaneFairfax
Member
Registered: 2007-02-23
Posts: 6,868

Re: Algebra

math123 wrote:

x and y are positive integers with the following two properties –
a) x3 – y3 is a perfect square, and
b) x2 – y2 is a perfect cube.
Find the smallest possible values of x and y.

Smallest possible values? That would be x = 1, y = 1, wouldn’t it?

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#4 2007-04-11 06:17:46

JaneFairfax
Member
Registered: 2007-02-23
Posts: 6,868

Re: Algebra

All right, my answer above was trivial. I suppose you want x > y for a non-trivial solution?

In that case, by trying out the first few values on an Excel spreadsheet, I have verified that Stanley’s answer is the correct one. up

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