You are not logged in.
Pages: 1
Please help, I have no clue how to do these. I have attached two exercises. Can you help me with the following questions: I would really appreciate your help.
13(a)
7e
8d, e, f
9a, c
12a, c, f
13(b)
1h
2d, f, i
3g, h
4b, d, f, h
5
6
7b, f
8d
10c, f
11a, c
12d, f
13d, e, f
http://www.forumadminforum.com/maths1.gif
http://www.forumadminforum.com/maths2.gif
http://www.forumadminforum.com/maths3.gif
http://www.forumadminforum.com/maths4.gif
Last edited by 12334545 (2007-04-02 22:58:48)
Offline
If your images are going to be big, it might be best to URL-link them instead of image-linking them. (As you can see, linked images are also resized so they dont exceed the width of the message box they are posted in.)
http://www.forumadminforum.com/maths1.gif
http://www.forumadminforum.com/maths2.gif
http://www.forumadminforum.com/maths3.gif
http://www.forumadminforum.com/maths4.gif
Ill have a look at the questions you have problems with and try and help you.
Last edited by JaneFairfax (2007-04-02 22:10:32)
Offline
thanks. appreciate your help.
Offline
I can't see those questions at all. Upload them somewhere, just don't post inline images. I just can't make out some of those questions.
Offline
I uploaded them to my website. They are here:
http://www.forumadminforum.com/maths1.gif
http://www.forumadminforum.com/maths2.gif
http://www.forumadminforum.com/maths3.gif
http://www.forumadminforum.com/maths4.gif
Cheers
Offline
I cant find the exercises for 13(a). Here are my hints for some of your 13(b) exercises. Im not going to do your homework for you; Ill just provide some guiding hints and you must complete the exercises yourself. Okay?
13(b)
1 h 243[sup]−2⁄5[/sup] = (1⁄243)[sup]2⁄5[/sup] = 1⁄(243[sup]2⁄5[/sup]); now evaluate the denominator.
2 d Note that 81 = 3[sup]4[/sup]. So √3∛81 = 3[sup]1⁄2[/sup](3[sup]4[/sup])[sup]1⁄3[/sup], and I leave you to do the rest.
2 f ∛(2[sup]3⁄2[/sup]) = (2[sup]3⁄2[/sup])[sup]1⁄3[/sup] = 2[sup]3⁄2×1⁄3[/sup]; the rest is simple.
2 i You just need to observe that 8 = 2[sup]3[/sup] and 4 = 2[sup]2[/sup].
3 g (9x[sup]2[/sup])[sup]3⁄2[/sup]×(8x[sup]3[/sup])[sup]−2⁄3[/sup] = 9[sup]3⁄2[/sup](x[sup]2[/sup])[sup]3⁄2[/sup]×8[sup]−2⁄3[/sup](x[sup]3[/sup])[sup]−2⁄3[/sup]. Dont forget to bring the [sup]3⁄2[/sup] in to the 9 and the [sup]−2⁄3[/sup] in to the 8.
3 h Its equal to a[sup]3⁄4+5⁄4−2[/sup]
4 b All right, heres the rule. (x[sup]a[/sup])[sup]b[/sup] = x[sup]a×b[/sup]. For example, (2[sup]2[/sup])[sup]3[/sup] = 2[sup]2×3[/sup] = 2[sup]6[/sup]. Get it?
4 d This is similar to 3g. The rule is (xy)[sup]a[/sup] = x[sup]a[/sup]y[sup]a[/sup]. For example, (2x[sup]1⁄2[/sup])[sup]4[/sup] = 2[sup]4[/sup](x[sup]1⁄2[/sup])[sup]4[/sup] = 16x[sup]2[/sup].
4 h Simplify the denominator and the numerator separately. Then simplify the whole fraction.
5 Again, the least confusing thing to do is the simplify the numerator and the denominator separately before simplifying the whole fraction. Then substitute the values for x and y and evaluate. It might also be useful to note that √6 = √(2×3) = √2×√3.
Thats it. I must stop for the time being. I might come back later to help you with the rest of your queries. (Or maybe someone else can do it.) Im totally exhausted now.
Last edited by JaneFairfax (2007-04-02 23:35:53)
Offline
they arnt homework, I want the solutions so I can study them for a test
Offline
Pages: 1