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**im really bored****Member**- Registered: 2005-05-12
- Posts: 76

factor completely: 128x^6 - 2y^6

I can expand it to: 2(8x^3 + y^3)(8x^3 - y^3)

I know it can be expanded more but how would that go?

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**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,657

2(8x^3 + y^3)(8x^3 - y^3)

Hmm .... the two similar terms can be further factored like this

(2x+y)*(4x^2-2xy+y^2) ==> 8x^3 - 4x^2y + 2xy^2 + 4x^2y - 2xy^2 + y^3 ==> 8x^3 + y^3

(2x-y)*(4x^2+2xy+y^2) ==> 8x^3 + 4x^2y + 2xy^2 - 4x^2y - 2xy^2 - y^3 ==> 8x^3 - y^3

So:

2(2x+y)*(4x^2-2xy+y^2)(2x-y)*(4x^2+2xy+y^2)

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

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**im really bored****Member**- Registered: 2005-05-12
- Posts: 76

Thanks, I was having some mental issues at the time...

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