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**Zeroface****Member**- Registered: 2006-12-29
- Posts: 11

You have a 6-sided dice with numbers on each side. 5 of the sides have 1 on them and 1 of the sides has 6 on it. The sides are also given letters which are A, B, C, D, E and F. I haven't said which letters correspond to which numbers. List all possible number and letter combinations the dice could have. Tip: Don't rush into it. Think.

0 can be nothing and something.

0

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**Toast****Real Member**- Registered: 2006-10-08
- Posts: 1,321

Well, I think in terms of combinatorics its

But then it is slightly ambiguous and probably a trick question so I will have to look closer

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

The question is indeed ambiguous. This is the way I interpreted it:

Any one of A, B, C, D, E or F can be assigned to the face with the 6 on it. All the rest of the letters get assigned to 1's. Therefore, there are 6 possible arrangements.

Why did the vector cross the road?

It wanted to be normal.

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**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,619

Combinations: 6

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

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**rida****Real Member**- Registered: 2006-09-25
- Posts: 839

Actually it's not because each 1 is a different face of the dice.I think you should think of a normal dice.

Dreams don't come true, you gotta make them come true.

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**Devantè****Real Member**- Registered: 2006-07-14
- Posts: 6,400

Zeroface wrote:

5 of the sides have 1 on them and 1 of the sides has 6 on it.

You've confused me with that statement, is the '1' used after the first '1' just part of txtspk?

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**Zeroface****Member**- Registered: 2006-12-29
- Posts: 11

Yes Devanté, it's just part of the text. But hey, you're just like me. I often

get confused with word problems.

0 can be nothing and something.

0

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**Simon****Member**- Registered: 2006-06-06
- Posts: 41

The question as asked, the answer is indeed 6 - as far as I can tell.

However, if it was a normal numbered dice covered by six letters - by my calculations the number of possible combinations between numbers and letters is 720!

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