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#1 2007-01-03 01:26:33

Zeroface
Member
Registered: 2006-12-29
Posts: 11

dice puzzle

You have a 6-sided dice with numbers on each side. 5 of the sides have 1 on them and 1 of the sides has 6 on it. The sides are also given letters which are A, B, C, D, E and F. I haven't said which letters correspond to which numbers. List all possible number and letter combinations the dice could have. Tip: Don't rush into it. Think.
dizzy


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#2 2007-01-03 07:16:12

Toast
Real Member
Registered: 2006-10-08
Posts: 1,321

Re: dice puzzle

Well, I think in terms of combinatorics its

But then it is slightly ambiguous and probably a trick question so I will have to look closer

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#3 2007-01-03 09:40:33

mathsyperson
Moderator
Registered: 2005-06-22
Posts: 4,900

Re: dice puzzle

The question is indeed ambiguous. This is the way I interpreted it:

Any one of A, B, C, D, E or F can be assigned to the face with the 6 on it. All the rest of the letters get assigned to 1's. Therefore, there are 6 possible arrangements.


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It wanted to be normal.

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#4 2007-01-03 10:31:29

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,535

Re: dice puzzle

Combinations: 6


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

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#5 2007-01-04 23:08:41

rida
Real Member
Registered: 2006-09-25
Posts: 839

Re: dice puzzle

Actually it's not because each 1 is a different face of the dice.I think you should think of a normal dice.


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#6 2007-01-05 05:34:04

Devantè
Real Member
Registered: 2006-07-14
Posts: 6,400

Re: dice puzzle

Zeroface wrote:

5 of the sides have 1 on them and 1 of the sides has 6 on it.

You've confused me with that statement, is the '1' used after the first '1' just part of txtspk?

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#7 2007-01-07 10:39:21

Zeroface
Member
Registered: 2006-12-29
Posts: 11

Re: dice puzzle

Yes Devanté, it's just part of the text. But hey, you're  just like me. I often
get confused with word problems. roll


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#8 2007-01-28 19:14:30

Simon
Member
Registered: 2006-06-06
Posts: 41

Re: dice puzzle

The question as asked, the answer is indeed 6 - as far as I can tell.

However, if it was a normal numbered dice covered by six letters - by my calculations the number of possible combinations between numbers and letters is 720! smile

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