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solve for x:
log x = sqrt(log x)
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Let's consider something a bit easier. Instead of having logs in there, let's just have a simple variable like u.
So now we have u = sqrt(u).
Squaring both sides will give you a quadratic in terms of u, which you can use to find the values of u. You can then work out what x would have to be.
Why did the vector cross the road?
It wanted to be normal.
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