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Um, this problem I found in the deductive proofs chapter is I think really hard, not quite sure how and where to start...
Thx...
(APE and CPB are similar triangles)
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Here:
Last edited by krassi_holmz (2006-12-09 03:44:52)
IPBLE: Increasing Performance By Lowering Expectations.
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Hey that's the lambda from counter-strike, isn't it?
Last edited by Toast (2006-12-09 03:08:25)
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Sorry for delaymant now it's edited.
IPBLE: Increasing Performance By Lowering Expectations.
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thanks krassi_holmz, ill try to understand that ... hehe
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There must be a mistake. We are told that AE/ED = m/n, but we already know that E bisects AD. Thus, AE=ED, so AE/ED = 1.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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Yeah, if we know the ratio then what is the use of pronumerals? Sadly I won't know the answer until I go back to school in a little under 2 months...
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First I thought the same, but the proof works for every m,n.
If E bisects AD, then E is (the center of the bisectors) in ΔABD, Let BD intersects with AC in K. Then BK=KD and AK is a bisector of the triangle. Thus AP=2PK. Whe we disect ΔBCD in the same way, we have: KC=3PK, SO AC/AP=(AP+PK+KC)/AP=6PK/2PK=3=2+1=2+n/m.
IPBLE: Increasing Performance By Lowering Expectations.
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