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coincidence with pi/2?
Hey, I looked on a graphing calculator and found that the limit of acos(x)-(pi/2) as x goes to 0 equals 0. Here's the only iffy part: is pi/2 a coincidence just popping up as some random number, or does the acos function acually really relate to pi/2?
Re: coincidence with pi/2?
its because acos is the inverse function of the cosine function. The reason pi appears is because we're working with radians.
A logarithm is just a misspelled algorithm.