Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °
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You are not logged in. #126 2006-11-28 02:13:01
Re: 0.9999....(recurring) = 1?LET,S MAKE THIS AS SIMPLE AS POSSIBLE! #127 2006-11-28 03:30:46
Re: 0.9999....(recurring) = 1?Anthony, your concept of decimal expansion is way off. It has nothing to do with "making something bigger". 0.999... is not smaller than 1. Real numbers are static, they don't grow or change. "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #128 2006-11-28 03:48:47
Re: 0.9999....(recurring) = 1?to be honest, i think the proof: is good enough without going into all this other math thats been mentioned. Last edited by luca-deltodesco (2006-11-28 03:49:13) The Beginning Of All Things To End. The End Of All Things To Come. #129 2006-11-29 01:07:54
Re: 0.9999....(recurring) = 1?To luca-deltodesco #130 2006-11-29 02:38:24
Re: 0.9999....(recurring) = 1?
is not infinity, nor is it an infinate number.
put it this way means in laymans terms, a 0. followed by an infinite number of 9's, so if you multiply this number by 10, you shift the decimal point one place to the right, and you get 9, followed by an infinite number of 9's, if you then take away the first number, every single 9 after the decimal point in the second number, is cancelled out by the 9's after the decimal point in the first number, and you're left with 9. Last edited by luca-deltodesco (2006-11-29 02:40:19) The Beginning Of All Things To End. The End Of All Things To Come. #131 2006-11-29 23:38:23
Re: 0.9999....(recurring) = 1?To luca-deltodesco! #132 2006-11-30 02:01:05
Re: 0.9999....(recurring) = 1?how is that a problem? The Beginning Of All Things To End. The End Of All Things To Come. #133 2006-11-30 04:45:26
Re: 0.9999....(recurring) = 1?Anthony wrote:
Then wrote:
That is the number of 9's. Non-finite. "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #134 2006-11-30 08:14:16
Re: 0.9999....(recurring) = 1?I just use: When asked a question like this. It's arguable, so I'm not saying that it's the absolute certain proof. #135 2006-11-30 09:02:17
Re: 0.9999....(recurring) = 1?tbh, i dont understand how anyone can argue this simple proof? you get people saying, oh but when you times it by 10, there must be on less 9 on the end of it, but that doesnt make sense, because thats treating infinity as a definate value. The Beginning Of All Things To End. The End Of All Things To Come. #136 2006-11-30 09:17:16
Re: 0.9999....(recurring) = 1?luca, the proof makes assumptions about binary operations performed on the decimal expansion of real numbers. Those assumptions turn out to be correct based on most standard definitions, but they are presented as assumptions none the less. "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #137 2006-11-30 23:56:22
Re: 0.9999....(recurring) = 1?If all Infinite Numbers equalled an Integer Number as in Infinite 0.9 = 1 it would be much easier to just call them Integer Numbers!! #138 2006-12-01 04:19:16
Re: 0.9999....(recurring) = 1?0.999... is an integer! "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #139 2006-12-02 01:05:56
Re: 0.9999....(recurring) = 1?To Ricky! #140 2006-12-02 04:47:24
Re: 0.9999....(recurring) = 1?
But that statement isn't true. There is a theorem which says: In other words, if I have two numbers: 0.375.... (note that ... here means I know there are other digits, but I don't know what they are) and 0.376.... (same thing here) Without knowing any other digits, I can state that 0.375... <= 0.376 but I can not state that 0.375... < 0.376... "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #141 2006-12-03 02:22:59
Re: 0.9999....(recurring) = 1?To Ricky! #142 2006-12-03 06:16:21
Re: 0.9999....(recurring) = 1?
Sure, you can state that. But you'd be wrong. I've tried to explain how in as many ways as possible. (At least) Three different proofs have been in these threads show that 0.999... = 1, and you have yet to level one criticism against any of them. You just keep stating that 0.999... does not equal 1. Frankly, I feel like I'm talking to a brick wall, and I'm getting tired of it. "In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..." #143 2006-12-04 01:14:01
Re: 0.9999....(recurring) = 1?To Ricky! #144 2006-12-04 01:36:15#145 2006-12-04 01:55:20#146 2006-12-04 04:26:39
Re: 0.9999....(recurring) = 1?i completely agree with ricky The Beginning Of All Things To End. The End Of All Things To Come. #147 2006-12-06 00:34:40
Re: 0.9999....(recurring) = 1?Genius! is seen in the eyes of others! when the problem is made clear! by the Genius! #148 2006-12-06 00:42:07
Re: 0.9999....(recurring) = 1?Anthony - how about you start to prove the proofs false instead of writing nonsense #149 2006-12-06 04:40:12
Re: 0.9999....(recurring) = 1?I know this has probably been said before but: - - - and so by the same steps: - - - (did I make any mistakes in the proof?) Last edited by Ehiness (2006-12-06 04:51:27) #150 2006-12-07 01:08:11
Re: 0.9999....(recurring) = 1?OK LET'S SEE IF SOMEONE CAN REALLY PROVE THIS QUESTION! |