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**Toast****Real Member**- Registered: 2006-10-08
- Posts: 1,321

So I was bored and decided to stuff around in paint (yes i know, I was pretty bored), I started with a circle, added a midpoint, then made all kinds of links and connections to come up with what is attached.

Then I noticed that the rectangles sorta looked familiar. Are they the golden ratio???

*Last edited by Toast (2006-11-27 02:25:16)*

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**mathsyperson****Moderator**- Registered: 2005-06-22
- Posts: 4,900

Ooh, very interesting. Let's see if we can work out the lengths of that highlighted rectangle.

If we say that the circle has a radius of 1, then its equation would be x² + y² = 1.

The upper-left corner of the rectangle lies on the circle and on a line drawn from the centre at 45° to the horizontal. From standard trigonometric triangles, this means that the co-ordinates of that point are (-1/√2, 1/√2), which in turn means that the length of the rectangle is 1/√2.

The lower-left corner has the same x co-ordinate as the upper-left corner, and it also lies on the line y = 1+x. We know that at that point, x = -1/√2, so that means that y = 1 - 1/√2.

So the difference in y-values of the upper-left and lower-left corners of the rectangle is given by (1/√2) - (1 - 1/√2) = √2 - 1.

We have now worked out that the highlighted rectangle has dimensions of 1/√2 and (√2 - 1).

To find the ratio of these, we need to divide one by the other.

(1/√2)/(√2 - 1) = 1/(2-√2) = (2+√2)/2 = 1+1/√2 ≈ 1.70

So, unless I've made a mistake somewhere, that rectangle isn't golden. Just quite close to it.

Very nice diagram though. It's amazing what you can produce with a simple drawing tool and a bit of boredom.

Why did the vector cross the road?

It wanted to be normal.

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**luca-deltodesco****Member**- Registered: 2006-05-05
- Posts: 1,470

but it begs the question... if you keep seperating it into smaller rectangles in the same fashion, will it remain ~1.7, or does it maybe diverge to phi?

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