You are not logged in.
Hey guys
How would you go about solving 2^x+1=5^x
Hi Thatcher, I just asked one of my friends and he said it is unsolvable using logs. He said you need to use calculus, which I haven't learnt.
Either by graphing or using a calculator I got x ≈ 0.563895524260.
A forum member should come along soon and help you with the method though, don't worry.
Last edited by Toast (2006-11-26 18:58:37)
Offline
yes, i tried with logs, but it is unsolvable via them, im not sure how you would apply calculus though, maybe youre friend could give a bit more help
The Beginning Of All Things To End.
The End Of All Things To Come.
Offline
Well, I can't ask him again till Thursday .
Try just analysing the graphs of
Last edited by Toast (2006-11-26 19:50:19)
Offline
I solved it using logs.
2^(x+1)=5^x
= 2^x * 2 = 5^x
= 2 = (5/2)^x
= log2 = x log (5/2)
therefore x = 0.756
Oh dear, you didn't include the brackets in the first question?
Oh well, good job on completing the question.;)
P.S. I'll still try and get back to you on
Last edited by Toast (2006-11-27 02:10:00)
Offline
those brackets make all the difference
The Beginning Of All Things To End.
The End Of All Things To Come.
Offline