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Hi can you check my working and help with the question,
Paul wants to make a 2 step staircase out of wood and gravel. He has two planks of wood that are 4 m and 1 m long. A wall of length 2.5 m runs along each side.
The steps PS and QR are parallel and the middle step TU is parallel to the others. To help plan construction, Paul considers a line from V to Q, passing through W and perpendicular to PS.
Let VW = x metres.
*The first diagram is the one given and the second is one I have created with extra lengths etc. I am not sure if the second diagram is correct
a) Prove that PQV ~ TQW
AA
b) Find an expression in terms of x for:
i) WQ
I got
ii) TW
c) Show that
This is where I got stumped, I don't know what to do here...
There are more but I lack the information to tackle them as yet...
Last edited by Toast (2006-11-13 23:53:10)
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First, I would suggest you to solve x out using the identity VQ=VW+WQ
Then, you can draw RB vertical to TU and PS with intersection A and B. I think you can work it out now.
Last edited by George,Y (2006-11-14 02:41:34)
X'(y-Xβ)=0
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Thanks... but I'm not quite sure what you're talking about... Where is B from RB? and what do you mean by 'vertical to' and where is A and B?
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Forget about that. Just draw a line starting from R and parallel to QV, then just name the intersections whatever you like.
X'(y-Xβ)=0
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Oh I see,
that would make TU =
Last edited by Toast (2006-11-15 18:00:05)
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