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Can anyone please explain how you work out the nth term for the Fibonacci Sequence. My maths teacher did explain but I got rather confused. Please Help.
The nth term in terms of n is very difficult to find. However, it is easy to express it in terms of the (n-1)th and (n-2)th term.
The Fibonacci sequence is defined by a[sub]1[/sub] = a[sub]2[/sub] = 1, and a[sub]n[/sub] = a[sub]n-1[/sub] + a[sub]n-2[/sub] for n>2.
So the first two numbers are both 1, the third is 1+1 = 2, the fourth is 1+2 = 3, then 2+3 = 5, 3+5 = 8, and so on.
Does that help?
Why did the vector cross the road?
It wanted to be normal.
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The nth term in terms of n is very difficult to find.
Difficult to find, maybe. You need to know a bunch of linear algebra before this is possible. However, anyone who understands algebra can use the formula:
Edit: Whoops, read the introductory post wrong.
Here is a fairly good link:
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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Ricky, 2 should replace 2[sup]n[/sup] in your formula
Last edited by George,Y (2006-11-15 15:03:31)
X'(y-Xβ)=0
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