how can i estimate the sine or tangent in a given triangle
and why is the sine of the 30 degrees equal to .5?
the exact question on my homework is: Estimate sinA and tanB in the given triangle ABC
then theres a picture of a right triangle thats labeled with A, B, and C and the 90 degree angle is shown
thats all it says and we never went over anything like this in class so I have no clue what to do
So maybe you could try to measure angle A (or B). If A is 30 degrees, then you can answer with sin 30 (=0.5), and tan 60 (=√3) (because if A is 30, B has to be 60).
If angle A is something else, maybe you could use your calculator
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
Or, because it's a right-angled triangle, then a possible simpler way would be to measure the sides of the triangle and find their ratios.
| \ c
b | \
C ----------- B
Sin A in this case would be length a divided by length c, and tan B would be b divided by a.
That might change depending on which angle is the right angle though.
Why did the vector cross the road?
It wanted to be normal.