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#1 2006-11-08 03:15:00

unique
Member
Registered: 2006-10-04
Posts: 419

Correct

Find the distance between the point (3,1) and the line y = x - 4

i did like this :

y = -2x + b < equation
1 = -2(2) + b < use (3,1)
1 = -6 + b < add 6
7 = b
y = -2x + 7 < completed equation
THAN
x - 4 = -2x + 7 < substitution
add 4 both sides
x = -2 + 11
3x = -2 + 11
3x = 9
x = 9/3 < solved for x
THAN
y = -2 (9/3) + 7
y = -6 + 7
y = 1 < solved for y
THAN distance formula
D = sqrt( ( (x2 - x1)^2 + (y2 - y1)^2 )
(3,1) and (3,1)
D = sqrt ( (3 - 3)^2 + (1 - 1)^2 )
D = sqrt( 0 + 0)
D = 0 < solved
answer is zero
correct?up


Desi
Raat Key Rani !

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#2 2006-11-08 06:10:07

John E. Franklin
Member
Registered: 2005-08-29
Posts: 3,562

Re: Correct

.
             .
             .          /
           o .         /
            o.        /
             o       /
             .o     /
             . o   /
             .  . /
             ....o...........
             .  / o
             . /   o
             ./     o
             /       o
             .        o
             .         o
             .
             .     square root of 2
             .     one down and one right.


igloo myrtilles fourmis

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#3 2006-11-08 07:42:26

unique
Member
Registered: 2006-10-04
Posts: 419

Re: Correct

so am i right?


Desi
Raat Key Rani !

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