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#1 2006-10-11 06:56:37

Devantè
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Registered: 2006-07-14
Posts: 6,400

Simplifying Simple i Terms (Intermediate)

Simplifying Simple i Terms - Intermediate Level

Express in simplest terms, in terms of i.

1. i[sup]1[/sup]
2. i[sup]3[/sup]
3. i[sup]0[/sup]
4. i[sup]19[/sup]
5. (i[sup]12[/sup])[sup]15[/sup]
6. i[sup]16[/sup] + i[sup]11[/sup]
7. i[sup]18[/sup] + i[sup]13[/sup]
8. (i[sup]6[/sup])[sup]30[/sup]
9. i[sup]25[/sup] - i[sup]20[/sup]
10. i[sup]29[/sup] × i[sup]14[/sup]
11. i[sup]23[/sup]
12. i[sup]36[/sup] ÷ i[sup]32[/sup]
13. i[sup]37[/sup] - i[sup]2[/sup]
14. (i[sup]28[/sup])[sup]33[/sup]
15. i[sup]8[/sup]
16. i[sup]34[/sup] × i[sup]44[/sup]
17. i[sup]50[/sup] + i[sup]40[/sup]
18. i[sup]49[/sup] ÷ i[sup]17[/sup]

-------------------

Last edited by Devanté (2006-10-11 06:58:06)

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#2 2006-10-11 07:25:26

Neha
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Registered: 2006-10-11
Posts: 173

Re: Simplifying Simple i Terms (Intermediate)

this is so easy
i^1 = i


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#3 2006-10-11 07:27:31

Neha
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Registered: 2006-10-11
Posts: 173

Re: Simplifying Simple i Terms (Intermediate)

2. i^3 = -1
3. i^0 = 0
4. i^19 = -i
5. 1


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#4 2006-10-11 07:33:25

Devantè
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Registered: 2006-07-14
Posts: 6,400

Re: Simplifying Simple i Terms (Intermediate)

Yes, but can you simplify them instead of answering them?

You can answer them too, if you like.

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#5 2006-10-11 07:34:14

unique
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Registered: 2006-10-04
Posts: 419

Re: Simplifying Simple i Terms (Intermediate)

that is easy i have done few problems like that in one of my test. very easy but only if you had a calculator.
there is a site if anyone is interested.....

http://www.google.com/intl/en/help/features.html#calculator


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#6 2006-10-11 07:35:15

unique
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Registered: 2006-10-04
Posts: 419

Re: Simplifying Simple i Terms (Intermediate)

http://www.algebrahelp.com/calculators/


Desi
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#7 2006-10-11 07:37:53

Devantè
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Registered: 2006-07-14
Posts: 6,400

Re: Simplifying Simple i Terms (Intermediate)

There is a calculator built into your computer, most likely.

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#8 2006-10-12 07:53:36

Kurre
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Registered: 2006-07-18
Posts: 280

Re: Simplifying Simple i Terms (Intermediate)

how can i^3 be -1, if you dont know the value of i?

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#9 2006-10-12 08:57:50

luca-deltodesco
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Registered: 2006-05-05
Posts: 1,470

Re: Simplifying Simple i Terms (Intermediate)

Kurre wrote:

how can i^3 be -1, if you dont know the value of i?

we do, i = √(-1)


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#10 2006-10-20 21:03:28

Kurre
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Registered: 2006-07-18
Posts: 280

Re: Simplifying Simple i Terms (Intermediate)

luca-deltodesco wrote:
Kurre wrote:

how can i^3 be -1, if you dont know the value of i?

we do, i = √(-1)

why?

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#11 2006-10-20 21:29:01

Devantè
Real Member
Registered: 2006-07-14
Posts: 6,400

Re: Simplifying Simple i Terms (Intermediate)

http://www.google.co.uk/search?hl=en&q=sqrt-1&btnG=Search&meta=

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#12 2006-11-02 02:00:31

Toast
Real Member
Registered: 2006-10-08
Posts: 1,321

Re: Simplifying Simple i Terms (Intermediate)

Hmm o_O how do you do the ones with massive powers?

Last edited by Toast (2006-11-02 23:13:59)

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#13 2006-11-02 03:37:35

saudi_boy
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Registered: 2006-11-01
Posts: 41

Re: Simplifying Simple i Terms (Intermediate)

78f740a410.jpg

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#14 2006-11-02 04:14:28

Toast
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Registered: 2006-10-08
Posts: 1,321

Re: Simplifying Simple i Terms (Intermediate)

thanks saudi_boy, that's quite clear and a lot simpler than my explanation smile

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#15 2006-11-02 05:00:28

saudi_boy
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Registered: 2006-11-01
Posts: 41

Re: Simplifying Simple i Terms (Intermediate)

smile smile smile smile

Last edited by saudi_boy (2006-11-02 05:02:55)

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#16 2006-11-02 05:47:18

saudi_boy
Member
Registered: 2006-11-01
Posts: 41

Re: Simplifying Simple i Terms (Intermediate)

Devanté wrote:

Simplifying Simple i Terms - Intermediate Level

Express in simplest terms, in terms of i.

1. i[sup]1[/sup]
2. i[sup]3[/sup]
3. i[sup]0[/sup]
4. i[sup]19[/sup]
5. (i[sup]12[/sup])[sup]15[/sup]
6. i[sup]16[/sup] + i[sup]11[/sup]
7. i[sup]18[/sup] + i[sup]13[/sup]
8. (i[sup]6[/sup])[sup]30[/sup]
9. i[sup]25[/sup] - i[sup]20[/sup]
10. i[sup]29[/sup] × i[sup]14[/sup]
11. i[sup]23[/sup]
12. i[sup]36[/sup] ÷ i[sup]32[/sup]
13. i[sup]37[/sup] - i[sup]2[/sup]
14. (i[sup]28[/sup])[sup]33[/sup]
15. i[sup]8[/sup]
16. i[sup]34[/sup] × i[sup]44[/sup]
17. i[sup]50[/sup] + i[sup]40[/sup]
18. i[sup]49[/sup] ÷ i[sup]17[/sup]

-------------------

Answer,,

1.       i

2.       -i

3.       i^o=  1

4.       i^19 = i^3    =    -i

5.       1

6.       1 - i

7.        i^18 + i^13  =  i^2 + i^1    =   -1 +i

8.        1

9.         i - 1

10.        i^29 + i^14 =    i^1 + i^2 =      -i

11.         i^23 = i^3     = -i

12.         1

13.          i + 1

14.           1

15.            1

16.            -1

17.             0

18.            1


smile:)

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