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find the quadratic equation with a lead corfficient of 1 and whose roots are 2 - 3i and 2 + 3i .
Live Love Life
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so, the quadratic is of the form
so plug in the two roots
so the quadratic is
lets try it out.
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The End Of All Things To Come.
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Thanks Luca
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Veda's(?) Law:
a=-(x1+x2) b=x1 x2
Proof (Incomplete)
If the solution is x1 and x2,
the equation must be able to transform into this form:
(x-x1)(x-x2)=0
<=>
xx-(x1+x2)x+(x1)(x2)=0
so
xx-(2+3i+2-3i)x+(2+3i)(2-3i)=0
X'(y-Xβ)=0
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