Math Is Fun Forum
  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

#1 2005-05-08 23:45:55

tOmd
Member
Registered: 2005-05-08
Posts: 1

Here's some Calculus!

How do I differentiate At^b * e^c?

Where t is the variable, e is euler's number and A, b and c are all constants.  I'm pretty sure I should be able to be able to simplify it to t = b/c or something like that.

Please Help!!!

Offline

#2 2005-05-09 00:46:34

MathsIsFun
Administrator
Registered: 2005-01-21
Posts: 7,559

Re: Here's some Calculus!

Hmmm ... if you treat (A*e^c) as a constant, call it "f" then you have:

f t^b

which is easily differentiated as

f t^b ln(b)

(derivative of a^x = a^x ln a)

There may be something special with your formula that I am not aware of, though!


"The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  - Leon M. Lederman

Offline

Board footer

Powered by FluxBB