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#1 2006-10-07 09:09:58

unique
Member
Registered: 2006-10-04
Posts: 419

Factoring

4x^(3n+2) - 6x^(4n+1)

common factor is = 2x^(3n + 2)

now what?:/


Desi
Raat Key Rani !

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#2 2006-10-07 10:23:19

polylog
Member
Registered: 2006-09-28
Posts: 162

Re: Factoring

Well I think that's all you can do. By taking out the common factor 2x^(3n + 2), you get:

I think it's a little difficult to see how to get 3x^(n-1) just like that, so perhaps its easier to do it this way:

Now here is the tricky part: if we factor the other 2x, we need to take out an x in the 3x^n term.

We do that by writing:

Because x multiplied by 3x^(n - 1) gives us the original 3x^n.

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#3 2006-10-07 10:30:22

Ricky
Moderator
Registered: 2005-12-04
Posts: 3,791

Re: Factoring

4x^(3n+2) - 6x^(4n+1)


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#4 2006-10-07 10:58:54

unique
Member
Registered: 2006-10-04
Posts: 419

Re: Factoring

thank you very much for the help


Desi
Raat Key Rani !

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