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**paulb203****Member**- Registered: 2023-02-24
- Posts: 246

Is there a way to find the centre of enlargement without drawing rays?

I see once I have drawn rays, and found the centre, that there is a pattern in the co-ordinates of the respective shapes, related to the scale factor, but is there a kind of reverse process or similar; use the co-ordinates of the shape given, and the scale factor, to find the centre (without the rays)?

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**Bob****Administrator**- Registered: 2010-06-20
- Posts: 10,512

The coordinates of two points before and after the enlargement is enough. Let's say they are (x1,y1) and (x2,y2) in the first shape and (X1,Y1) and (X2,Y2) in the transformed shape.

Find the equation of the line joining (x1,y1) to (X1,Y1) and also the other similar line. These are the rays but expressed algebraically.

Find where they cross. that's the centre.

You could probably construct a formula for this and then you're independent of a graph entirely.

Bob

If the centre is C and A = (x1,y1) and B = (X1,Y1) then CB/CA gives the scale factor.

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Sometimes I deliberately make mistakes, just to test you! …………….Bob

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**paulb203****Member**- Registered: 2023-02-24
- Posts: 246

Thanks, Bob.

"Find where they cross. that's the centre."

Can that be worked out from the two equations, without drawing the two rays?

I've worked out the following two equations from an example;

y=2x-2

y=(1/2)x-(1/2)

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**Bob****Administrator**- Registered: 2010-06-20
- Posts: 10,512

Equating those values of y gives

In general

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Sometimes I deliberately make mistakes, just to test you! …………….Bob

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**paulb203****Member**- Registered: 2023-02-24
- Posts: 246

Thanks, Bob.

Why do we equate the two values of x?

I managed to follow your algebra for finding the value of x, thanks; great practice for me!

And the co-ordinates for the centre matched up with my graph, where the rays met (1,0), which was satisfying.

But why, once we established that x=1, do we conclude that y=0?

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**Bob****Administrator**- Registered: 2010-06-20
- Posts: 10,512

Why do we equate the two values of x?

Actually I put the two ys equal and solved for x. But I could have eliminated the xs and solved for y. That would have worked as well.

If the lines cross then, at the intersection point they both have the same x and y coordinates. You have two equations so it becomes a simultaneous equations problem. What are the values of x and y that fit both equations simultaneously. So eliminate one unknown and solve for the other. As both equations are in the form y = function of x, the quickest way to an answer is to make the two functions of x equal and find the one x that works for both. Once you have that you can substitite that x value into either equation to get y. It works whichever equation you choose because that y is the one that fits in both equations.

Many routes to the same answer:

y = 2x -2

y = x/2 -1/2

Subtract the left hand sides and the right hand sides:

0 = 3x/2 - 3/2 so 3x/2 = 3/2 so x=1

substitute in y = 2x -2 ..... y = 2times 1 -2 = 0

substitute in y = x/2 -1/2 ...... y = 1/2 - 1/2 = 0

Make x the subject of each:

x = (y+2)/2

x = 2(y+1/2)

Set these equal

Substitiute in y = 2x - 2 ....... 0 = 2x - 2 ....... x = 1

Substitite in y = x/2 - 1/2 ....... 0 = x/2 - 1/2 ........ x/2 = 1/2 ....... x = 1

Bob

Children are not defined by school ...........The Fonz

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

Sometimes I deliberately make mistakes, just to test you! …………….Bob

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**paulb203****Member**- Registered: 2023-02-24
- Posts: 246

Thanks, Bob.

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