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#1 2006-09-24 15:38:02




Given that d^2y/dx^2 = 6x + 4/x^3, and that y = 1 when x= 1, and that y = 5 when x = 2, find an expression for y in terms of x.
I realize that I have to get to a simultaneous equation somehow, but I'm not sure how.

The acceleration a m s^-2, of a particle at time t seconds is given by the formula a = 30t. At time t=0 the particle is moving through the origin with a velocity of 2 m s^-1. 
Find an expression, in terms of t, for the displacement of the particle at time t.
Find an expression, in terms of t, for the velocity of the particle at time t.
How do I go about this one?


#2 2006-09-24 18:37:34

Registered: 2006-05-05
Posts: 1,470

Re: Integration

take away first equation from second

to find velocity, and displacement, you take the first and second integral

except, obviously by definition, displacement at t = 0, is 0, because it hasnt moved yet, so you just forget about c for displacement.

Last edited by luca-deltodesco (2006-09-24 18:39:29)

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