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#1 2006-09-20 07:53:36

Neela
Guest

calculus.. again.

I'm back with another question.


y = (1/ cos x) + (1 / sin x).

I have to find the coordinates of the point on this curve in the range 0 <_ x, <_ pi, where the gradient is zero.

I have found the derivative of the function.

dy/dx = (sin^3x - cos^3x) / (sin^2x cos^2x).

How do I proceed from here?

Thanks so much

#2 2006-09-20 09:15:46

luca-deltodesco
Member
Registered: 2006-05-05
Posts: 1,470

Re: calculus.. again.


i know the next step isnt correct as of such, but it will let you find atleast one root

a root which happens to be within your range.

plugging into the first equation



/* if this aint right, someone tell me where i went wrong? */

Last edited by luca-deltodesco (2006-09-20 09:22:28)


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#3 2006-09-20 13:57:08

Prakash Panneer
Member
Registered: 2006-06-01
Posts: 110

Re: calculus.. again.

Hi luca-deltodesco,

Yes, you are right.

up


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