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**George,Y****Member**- Registered: 2006-03-12
- Posts: 1,372

I designed a server sytem and its backup plan.

To simplify, there are a pair of server programs each using one hard server.

And redundancy makes a pair of them.

This is the original plan:

A1 A2

| |

B1 B2

But since A's are equivalent and B's are equivalent I come up this:

A1 A2

| X |

B1 B2

A1-B2 and A2-B1 also works.

Now comes the fun part: reliability

Suppose the manufacturer can only guarantee the failure rate of each hard server as little as p

How is the overall A-B server system failure rate?

For the straight pair, the failure situation is not a single pair could work (They both fail)

[1-(1-p)(1-p)]^2 = [p(2-p)]^2

For the cross enhanced, the success situation is both A's and B's have at least one functional:

[1-pp]^2

So the survival rate of the straight is S(p) = 1 - [p(2-p)]^2 ; failure rate s(p) = [p(2-p)]^2

the survival rate of cross enhanced is C(p) = [1-pp]^2 ; failure rate c(p) = 1 - (1-pp)^2

Usually, s(p) = 2c(p)

Or the cross pairing reduces the original failure rate by half.

**X'(y-Xβ)=0**

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**George,Y****Member**- Registered: 2006-03-12
- Posts: 1,372

s(p)/c(p) -> 2 as p->0

**X'(y-Xβ)=0**

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