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**Max90****Member**- Registered: 2017-09-23
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A committee of 4 people is to be selected from 10 people. How many ways can this be done?

I presume this implies Combination WITHOUT repetition, and if so I got 210. The formula I used was n!/k!(n-k)!

Thus, 10*9*8*7/4*3*2 = 210

Now a follow up question is: If there are 5 men and 5 women, what is the probability there would be at least 1 woman?

\How do I do this? What formula do I use?

*Last edited by Max90 (2017-10-31 14:55:02)*

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Hi Max90,

Welcome to the forum. Have you heard of the binomial distribution?

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