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You are not logged in. #1 20060830 01:53:41
permutation problem..can u please help me with this? Here's the problem: #2 20060830 03:07:37
Re: permutation problem..You have 26 * 25 * 24 combinations of letters you can use assuming no duplicates. That's 15600. You can choose from 1 to 9 for the 1st digit. For the second digit you have 9 choices also; 0 through 9 except for whatever was picked for the 1st digit. The 3 digit you have 8 choices. So 9*9*8 possibilities for the numeric part of your plate. That's 648. Multiply those two numbers together: 648 * 15600 = 10,108,800. #4 20060830 14:32:52
Re: permutation problem..I think the possibilities of 3lettered group are 26x26x26=17576, of 3digitted group are 10x10x10=1000, but without 0 being the first number (000099), we have 1000100=900 possibilities. Multiply them together, we have 17576x900=15818400 possibilities for one pattern ABC123 or 123ABC. If both patterns are applied, multiply it by 2. #5 20060830 14:45:41
Re: permutation problem..
I miss this line. Never mind my post above. #6 20060830 19:34:31
Re: permutation problem..Not a problem, brian ... (join the forum!) "The physicists defer only to mathematicians, and the mathematicians defer only to God ..."  Leon M. Lederman 