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**jacks****Member**- Registered: 2012-11-21
- Posts: 132

The number of triangle which are obtuse and points

are the feet ofperpendiculars drawn from vertices on the opposite sides is

*Last edited by jacks (2016-07-20 21:40:33)*

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**thickhead****Member**- Registered: 2016-04-16
- Posts: 1,086

**{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha{Gods rejoice at those places where ladies are respected.}**

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**jacks****Member**- Registered: 2012-11-21
- Posts: 132

Yes Thickhead, Yould you like to explain me , Thanks

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**thickhead****Member**- Registered: 2016-04-16
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If we join L,M and N the feet of perpendiculars from A,B,c to opposite sides to form a triangle it is known that the in center of this triangle is the ortho center of ABC. This only applies to acute angle triangle ABC. If ABC is obtuse then the orthocenter of ABC lies outside LMN but a circle can be drawn from ortocenter touching one side of LMN and the other two extended sides. Thus there will be 3 configurations for obtuse angled triangle.

**{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha{Gods rejoice at those places where ladies are respected.}**

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**thickhead****Member**- Registered: 2016-04-16
- Posts: 1,086

the 3 outcenters (as compared to in centers) are (50,-5) (5,10)(15,30) incenter is (10,15)

for (50,-5) The triangle ABC will have vertices A(5,10) B(10,15) C(15,30) the angles are

*Last edited by thickhead (2016-07-22 22:30:17)*

**{1}Vasudhaiva Kutumakam.{The whole Universe is a family.}(2)Yatra naaryasthu poojyanthe Ramanthe tatra Devataha{Gods rejoice at those places where ladies are respected.}**

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**jacks****Member**- Registered: 2012-11-21
- Posts: 132

Thanks Thickhead for nice explanation

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