OK So here is my problem:
"A certain prescription drug produces side effects in 3% of the patients. Three patients that have taken this drug are selected at random. Find the probability that
a.) All three had side effects
b.) None of the three had side effects."
I am not even sure where to begin on this one so any help would be greatly appreciated. Thanks
OK so after looking around this is what I came up with. Please let me know if this is correct or if I am way off track. Thanks
a.) .03*.03*.03= .000027=.0027% chance
b.) .97*.97*.97= .912673= 91.26% chance
What you have is exactly right. Nicely done.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."