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#1 2015-04-12 18:04:14

mrpace
Member
Registered: 2012-08-16
Posts: 74

Solve the following differential equation.

Solve:

2y∂u - 3x∂u + 2xyu = xy
   ∂x       ∂y


given that along Y^2 = (-1/2)x^2

                      u = 1/2  +  cos(x)e^(x^2/2)

Any idea?

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