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**Lukie****Guest**

I need to find "a" when ax² + 0x + 185

Please Help,

Luke

**kempos****Member**- Registered: 2006-01-07
- Posts: 77

when ax^2 + 0x + 185 what?

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**Lukie****Guest**

ax^2 + bx + c = 0 is the normal parabolic eqaution.

i need to find "a" when b = 0 and c = 185

please help

**kempos****Member**- Registered: 2006-01-07
- Posts: 77

sorry, i dont get it :-(

maybe i'm just to tired :-)

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**MATHSKITZO****Member**- Registered: 2006-05-08
- Posts: 22

I don't get it either

*Last edited by MATHSKITZO (2006-05-11 00:07:41)*

'Math is not a means to arrive at truth, Math IS the only truth!'

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**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,535

ax² + 0x + 185 = 0

ax² + 185 = 0

ax² = -185

a = -185/x²

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**George,Y****Member**- Registered: 2006-03-12
- Posts: 1,306

You should find another constraint to determine a.

3 parameters a, b and c, at least need 2 constraints to determine, according to my experience.

**X'(y-Xβ)=0**

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**Ricky****Moderator**- Registered: 2005-12-04
- Posts: 3,791

Right. a can be anything you want it. For example:

4x² + 0x + 185 = 0

104x² + 0x + 185 = 0

Are both perfectly fine equations. In fact, anything that you want to put in for 'a' works. So you have an infinite amount of solutions. Either this is the answer, or there is something about the question you are missing or not understanding. Could you post the entire question here?

"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."

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