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I was doing my maths hw when i got stuck on this M1 exam paper question.3. In a simple model for the motion of a car, its velocity,v, at time t seconds is given by v=(3t² - 2t + 8)i + (5t +6)j ms-¹a) Calculate the speed of the car when t=0.b) Find the values of t for which the velocity of the car is parallel to the vector (i+j).c) Why would this model not be appropriate for large values of t?I have done a) and made it 10ms-¹ which agrees with the answers i have been supplied. I am confused on how to do b) and any help would be appreaciated.Thanks
if a vector ai+bj is parallel to the vector i+j, it means ai+bj=k(i+j)since i and j are not parallel to each other, the only solution is a=k, b=kHence a=bfor your question3t² - 2t + 8=5t +63t²-7t+2=0(3t-1)(t-2)=0t=1/3 or t=2for c, the speed cannot grow up forever.
Neat Answer.Oh, and "c" is because of "c"
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