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**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,626

Another one: Cars Across the Desert Puzzle

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 105,688

Hi;

A very interesting problem. I could not find a solution with 3 cars. Have you ever seen a proof or any argument why 4 are necessary?

**In mathematics, you don't understand things. You just get used to them.****If it ain't broke, fix it until it is.****No great discovery was ever made without a bold guess. **

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**MathsIsFun****Administrator**- Registered: 2005-01-21
- Posts: 7,626

No I haven't.

But I have been thinking how to rescue the empty cars.

"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman

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**Creeper_Mode****Member**- Registered: 2013-10-21
- Posts: 2

Nehushtan wrote:

Only one question. It doesn't says that you will be able to tow another car! Even if you can. It will use more patrol that's wouldn't take you to quarter a desert per car!

Creeper_mode - Amateur Math solver

Love Logic Puzzles.

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**Grimbal****Member**- Registered: 2013-11-24
- Posts: 7

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**MAJ Trey****Member**- From: Maryland, USA
- Registered: 2014-07-30
- Posts: 1

[hide = 4 Cars without salvage]My solution also uses 4 cars, but each car should be able to return to the start point (3 cars) or get to the other side (1 car)

Each car has a different role and travels different distances

Car 1: Travel 1/6, Transfer 1/6 to either Car 2 or Car 3, Return 1/6

Car 2: Travel 1/6, Receive 1/6 from Car 1, Travel another 1/6, Transfer 1/6, Return 1/6, Receive 1/6 from Car 1, Return 1/6

Car 3: Travel 1/6, Receive 1/6 from Car 1, Travel another 1/6, Receive 1/6 from Car 2, Travel 1/6, Transfer 1/6 to Car 4, Return 1/6, Receive 1/6 from Car 2, Travel 1/6, Receive 1/6 from Car 1, Travel 1/6

Car 4 [With VIP]: Travel 1/6, Receive 1/6 from Car 1, Travel another 1/6, Receive 1/6 from Car 2, Travel 1/6, Receive 1/6 to Car 4, Travel 1/2 to destination

The obvious issue is the time waiting for Cars 1 and 2 to constantly return and refill. But it is feasible.[/hide]

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