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#1 2014-07-10 16:06:48

lovelylola
Member
Registered: 2014-07-09
Posts: 2

Geometry Proof ~Similarity~

Quadrilateral WXYZ has right angles at angle W and angle Y and an acute angle at angle X. Altitudes are dropped from X and Z to diagonal WY, meeting WY at O and P. Prove that OW = PY.


My name is Lola, and indeed I am quite lovely.

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#2 2014-07-25 08:53:53

bob bundy
Moderator
Registered: 2010-06-20
Posts: 6,294

Re: Geometry Proof ~Similarity~

Hi Lola,

Welcome to the forum.  smile

Just got back from a holiday, so I've only just seen this.

Note:  WXYZ is a cyclic quadrilateral.  ie. There is a circle (let's say centre C) that goes through all four points.

If you extend ZP until it cuts the circle again at Q; and extend XO until it cuts the circle again at R,

then

QZ is parallel to XR, and CQ = CZ = CR = CX

so

QP = XO and PZ = OR.

There is a property of any two chords in a circle that

WP.PY = QP.PZ

and

OY.OW = XO.OR

Thus

WP.PY = OY.OW  => WP(PO+OY) = OY(WP+PO)

=> WP.PO + WP.OY = OY.WP + OY.PO

Simplify to WP = OY and the required result follows.

If you've not met any of those theorems for a circle, post back.  smile

Bob


You cannot teach a man anything;  you can only help him find it within himself..........Galileo Galilei

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