And another in the Diff Eq series: Homogeneous Differential Equations
The main weakness in this page is no explanation of why they are "Homogeneous". I played with linking f(zx,zy) = z^n f(x,y) to dy/dx=F(x/y) form but failed. If anyone knows a user-friendly way of explaining why "Homogeneous" that would be nice.
Comments, suggestions and error checking welcome.
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
The page on Homogeneous Differential Equations is well made.
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First example can have a negative solution also. Second example is correct. You can solve for y in the third example.
If it ain't broke, fix it until it is.
Thanks bobby ... yes and yes: ±√(2x^2+c) − x is what I get now.