And another in the Diff Eq series: Homogeneous Differential Equations
The main weakness in this page is no explanation of why they are "Homogeneous". I played with linking f(zx,zy) = z^n f(x,y) to dy/dx=F(x/y) form but failed. If anyone knows a user-friendly way of explaining why "Homogeneous" that would be nice.
Comments, suggestions and error checking welcome.
"The physicists defer only to mathematicians, and the mathematicians defer only to God ..." - Leon M. Lederman
The page on Homogeneous Differential Equations is well made.
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First example can have a negative solution also. Second example is correct. You can solve for y in the third example.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Thinking is cheating.
Thanks bobby ... yes and yes: ±√(2x^2+c) − x is what I get now.